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(5a+3)=(4a^2-0.75)
We move all terms to the left:
(5a+3)-((4a^2-0.75))=0
We get rid of parentheses
5a-((4a^2-0.75))+3=0
We calculate terms in parentheses: -((4a^2-0.75)), so:We get rid of parentheses
(4a^2-0.75)
We get rid of parentheses
4a^2-0.75
Back to the equation:
-(4a^2-0.75)
-4a^2+5a+0.75+3=0
We add all the numbers together, and all the variables
-4a^2+5a+3.75=0
a = -4; b = 5; c = +3.75;
Δ = b2-4ac
Δ = 52-4·(-4)·3.75
Δ = 85
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{85}}{2*-4}=\frac{-5-\sqrt{85}}{-8} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{85}}{2*-4}=\frac{-5+\sqrt{85}}{-8} $
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